Question

Differentiate the following w. r. t. x. : x³ log x

Answer 1

Let y = (x³ log x)

Differentiating w.r.t. x, we get

`dy/dx = d/dx x^3 log x`

= `x^3 d/dx(logx) + (logx) d/dx(x^3)`

= `x^3xx1/x + (log x)(3x^2)`

= x² + 3x² log x