English

Differential coefficient of sec(tan−1 x) is ______. - Mathematics

Advertisements
Advertisements

Question

Differential coefficient of sec(tan−1 x) is ______.

Options

  • `x/(1 + x^2)`

  • `x sqrt(1 + x^2)`

  • `1/sqrt(1 + x^2)`

  • `x/sqrt(1 + x^2)`

MCQ
Sum
Advertisements

Solution

`x/sqrt(1 + x^2)`

Explanation:

y = sec(tan−1 x)

`dy/dx = d/dx sec(tan^-1 x)`

`dy/dx =  sec(tan^-1 x). tan(tan^-1 x) × d/dx (tan^-1 x)`

`dy/dx =  sec(tan^-1 x). tan(tan^-1 x) × 1/sqrt(1 + x^2)`

`dy/dx =  sec(tan^-1 x). x × 1/sqrt(1 + x^2)    ...[tan(tan^-1 x) = x]`

`dy/dx =  y × x × 1/sqrt(1 + x^2)`

`dy/dx = y(x/sqrt(1 + x^2))`

`dy/dx = (x/sqrt(1 + x^2))y`

This is the equation of differential equation which have coefficient `x/sqrt(1 + x^2)`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 11: Differentiation - Exercise 11.10 [Page 119]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 11 Differentiation
Exercise 11.10 | Q 4 | Page 119

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Prove that `y=(4sintheta)/(2+costheta)-theta `


Differentiate the following functions from first principles eax+b.


Differentiate tan (x° + 45°) ?


Differentiate sin2 (2x + 1) ?


Differentiate \[\frac{e^{2x} + e^{- 2x}}{e^{2x} - e^{- 2x}}\] ?


Differentiate \[\log \sqrt{\frac{x - 1}{x + 1}}\] ?


 If \[y = \sqrt{x + 1} + \sqrt{x - 1}\] , prove that \[\sqrt{x^2 - 1}\frac{dy}{dx} = \frac{1}{2}y\] ?


Differentiate 

\[\tan^{- 1} \left( \frac{\cos x + \sin x}{\cos x - \sin x} \right), \frac{\pi}{4} < x < \frac{\pi}{4}\] ?


If \[\sqrt{1 - x^2} + \sqrt{1 - y^2} = a \left( x - y \right)\] , prove that \[\frac{dy}{dx} = \frac{\sqrt{1 - y^2}}{1 - x^2}\] ?


If \[xy = 1\] prove that \[\frac{dy}{dx} + y^2 = 0\] ?


If \[\sin^2 y + \cos xy = k,\] find  \[\frac{dy}{dx}\] at \[x = 1 , \] \[y = \frac{\pi}{4} .\] 


If \[x^y + y^x = \left( x + y \right)^{x + y} , \text{ find } \frac{dy}{dx}\] ?


If \[\left( \sin x \right)^y = \left( \cos y \right)^x ,\], prove that \[\frac{dy}{dx} = \frac{\log \cos y - y cot x}{\log \sin x + x \tan y}\] ?


If \[e^{x + y} - x = 0\] ,prove that \[\frac{dy}{dx} = \frac{1 - x}{x}\] ?


If  \[\left( \sin x \right)^y = x + y\] , prove that \[\frac{dy}{dx} = \frac{1 - \left( x + y \right) y \cot x}{\left( x + y \right) \log \sin x - 1}\] ?

 


Find the derivative of the function f (x) given by  \[f\left( x \right) = \left( 1 + x \right) \left( 1 + x^2 \right) \left( 1 + x^4 \right) \left( 1 + x^8 \right)\] and hence find `f' (1)` ?

 


If \[y^x + x^y + x^x = a^b\] ,find \[\frac{dy}{dx}\] ?


If  \[\left( \cos x \right)^y = \left( \cos y \right)^x , \text{ find } \frac{dy}{dx}\] ?

 


\[\text{ If } \left( x - y \right) e^\frac{x}{x - y} = a,\text{  prove that y }\frac{dy}{dx} + x = 2y\] ?

If \[x = a \left( \frac{1 + t^2}{1 - t^2} \right) \text { and y } = \frac{2t}{1 - t^2}, \text { find } \frac{dy}{dx}\] ?


If \[x = a \left( \theta - \sin \theta \right) and, y = a \left( 1 + \cos \theta \right), \text { find } \frac{dy}{dx} \text{ at }\theta = \frac{\pi}{3} \] ?

 


Write the derivative of sinx with respect to cos x ?


Differentiate \[\sin^{- 1} \left( 2x \sqrt{1 - x^2} \right)\] with respect to  \[\sec^{- 1} \left( \frac{1}{\sqrt{1 - x^2}} \right)\], if \[x \in \left( 0, \frac{1}{\sqrt{2}} \right)\] ?


Differentiate \[\sin^{- 1} \left( \frac{2x}{1 + x^2} \right)\] with respect to \[\cos^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right), \text { if } 0 < x < 1\] ?


Differentiate \[\tan^{- 1} \left( \frac{x - 1}{x + 1} \right)\] with respect to \[\sin^{- 1} \left( 3x - 4 x^3 \right), \text { if }- \frac{1}{2} < x < \frac{1}{2}\] ?


\[\sin^{- 1} \sqrt{1 - x^2}\] with respect to \[\cot^{- 1} \left( \frac{x}{\sqrt{1 - x^2}} \right),\text { if }0 < x < 1\] ? 


If \[y = \log_a x, \text{ find } \frac{dy}{dx} \] ? 


If \[y = \log \left( \frac{1 - x^2}{1 + x^2} \right), \text { then } \frac{dy}{dx} =\] __________ .


Find the second order derivatives of the following function  log (sin x) ?


Find \[\frac{d^2 y}{d x^2}\] where \[y = \log \left( \frac{x^2}{e^2} \right)\] ?


If y = cos−1 x, find \[\frac{d^2 y}{d x^2}\] in terms of y alone ?


\[\text { If x } = \cos t + \log \tan\frac{t}{2}, y = \sin t, \text { then find the value of } \frac{d^2 y}{d t^2} \text { and } \frac{d^2 y}{d x^2} \text { at } t = \frac{\pi}{4} \] ?


\[\text { If y } = x^n \left\{ a \cos\left( \log x \right) + b \sin\left( \log x \right) \right\}, \text { prove that } x^2 \frac{d^2 y}{d x^2} + \left( 1 - 2n \right)x\frac{d y}{d x} + \left( 1 + n^2 \right)y = 0 \] Disclaimer: There is a misprint in the question. It must be 

\[x^2 \frac{d^2 y}{d x^2} + \left( 1 - 2n \right)x\frac{d y}{d x} + \left( 1 + n^2 \right)y = 0\] instead of 1

\[x^2 \frac{d^2 y}{d x^2} + \left( 1 - 2n \right)\frac{d y}{d x} + \left( 1 + n^2 \right)y = 0\] ?


If x = t2 and y = t3, find \[\frac{d^2 y}{d x^2}\] ?


If y = |x − x2|, then find \[\frac{d^2 y}{d x^2}\] ?


If y = axn+1 + bx−n, then \[x^2 \frac{d^2 y}{d x^2} =\] 

 


If y = (sin−1 x)2, then (1 − x2)y2 is equal to

 


If \[\frac{d}{dx}\left[ x^n - a_1 x^{n - 1} + a_2 x^{n - 2} + . . . + \left( - 1 \right)^n a_n \right] e^x = x^n e^x\] then the value of ar, 0 < r ≤ n, is equal to 

 


Differentiate `log [x+2+sqrt(x^2+4x+1)]`


f(x) = xx has a stationary point at ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×