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Diazonium salt decomposes as C⁢𝐴6⁢H⁡𝐴5⁢N⁢+2⁢Cl⁢𝐴−C⁢𝐴6⁢H⁡𝐴5⁢Cl+N⁢𝐴2 At 0°C, the evolution of N2 becomes two times faster when the initial concentration of the salt is doubled. Therefore it is - Chemistry (Theory)

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Question

Diazonium salt decomposes as
\[\ce{C6H5N{^+_2}Cl- -> C6H5Cl + N2}\]

At 0°C, the evolution of N2 becomes two times faster when the initial concentration of the salt is doubled. Therefore it is ______.

Options

  • a first order reaction

  • a second order reaction

  • independent of the initial cone, of the salt

  • a zero order reaction

MCQ
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Solution

Diazonium salt decomposes as
\[\ce{C6H5N{^+_2}Cl- -> C6H5Cl + N2}\]

At 0°C, the evolution of N2 becomes two times faster when the initial concentration of the salt is doubled. Therefore it is a first order reaction.

Explanation:

The given reaction is \[\ce{C6H5N{^+_2}Cl- -> C6H5Cl + N2}\]

It is given that when the initial concentration is doubled, the rate of nitrogen evolution also doubles.

This implies:

Rate ∝ \[\ce{[C6H5N{^+_2}Cl-]^{1}}\]

So, the reaction follows a first-order rate law.

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Chapter 4: Chemical Kinetics - OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS [Page 267]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 4 Chemical Kinetics
OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS | Q 20. | Page 267
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