Advertisements
Advertisements
Question
Diagonals of a quadrilateral ABCD bisect each other. If ∠A = 35º, determine ∠B.
Advertisements
Solution
Given: Diagonals of a quadrilateral ABCD bisect each other.
So, ABCD is a parallelogram.
Now, ∠A + ∠B = 180° ...[Adjacent angles of a parallelogram are supplementary]
Since, 35° + ∠B = 180°
∠B = 180° – 35°
∠B = 145°
APPEARS IN
RELATED QUESTIONS
The diagonals AC and BD of a parallelogram ABCD intersect each other at the point O. If ∠DAC = 32º and ∠AOB = 70º, then ∠DBC is equal to ______.
Diagonals of a parallelogram are perpendicular to each other. Is this statement true? Give reason for your answer.
E and F are points on diagonal AC of a parallelogram ABCD such that AE = CF. Show that BFDE is a parallelogram.
Points P and Q have been taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AP = CQ (Figure). Show that AC and PQ bisect each other.
In a parallelogram ABCD, AB = 10 cm and AD = 6 cm. The bisector of ∠A meets DC in E. AE and BC produced meet at F. Find the length of CF.
In the following figure, AB || DE, AB = DE, AC || DF and AC = DF. Prove that BC || EF and BC = EF.
P and Q are points on opposite sides AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. Show that PQ is bisected at O.
ABCD is a rectangle in which diagonal BD bisects ∠B. Show that ABCD is a square.
If diagonals of a quadrilateral bisect each other, it must be a parallelogram.
Two sticks each of length 5 cm are crossing each other such that they bisect each other. What shape is formed by joining their endpoints? Give reason.
