Question

Determine the nature of root of the quadratic equation.

m² - 2m + 1 = 0

Answer 1

Given:

⇒ m² - 2m + 1 = 0 compare with ax² + bx + c = 0 

We get,

⇒ a = 1, b = - 2, c = 1

The value of the discriminant is

∴ b² - 4ac
= (-2)² - 4(1) (1) 
= 4 - 4
= 0

∴ b² - 4ac = 0. Hence, roots are real and equal.