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Question
Determine k so that the equation 4x2 + kx + 1 = 0 will have just one real solution?
Options
3
4
5
6
MCQ
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Solution
4
Explanation:
Let K = 4, 4x2 + 4x + 1 = 0
4x2 + 2x + 2x + 1 = 0
2x(2x + 1) + 1(2x + 1) = 0
∴ (2x + 1)2 = 0, we get, x = `- 1/2` is just one real solution.
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