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Question
ΔDEF ~ ΔMNK. If DE = 5, MN = 6, then find the value of `"A(ΔDEF)"/"A(ΔMNK)"`
Solution
Given: ∆DEF ≅ ∆MNK
by Areas of similar triangles.
`∴ ["A(Δ DEF)"]/["A(Δ MNK)"] = ("DE"^2)/("MN"^2)`
Ratio of areas of Similar Triangles = Ratio of Squares of corresponding sides
`∴ ["A(Δ DEF)"]/["A(Δ MNK)"] = 5^2/6^2 = 25/36`
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