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Question
`d/dx[cot^-1(sqrtx)]` = ______
Options
cosec-1 x
`(-1)/(2sqrtx(1 + x))`
`(-1)/(1 + x)`
`(2sqrtx)/(1 + x)`
MCQ
Fill in the Blanks
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Solution
`d/dx[cot^-1(sqrtx)]` = `underline((-1)/(2sqrtx(1 + x)))`
Explanation:
`d/dx[cot^-1(sqrtx)] = (-1)/(1 + (sqrtx)^2) . 1/(2sqrtx) = (-1)/(2sqrtx(1 + x))`
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Derivative of Inverse Functions
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