Question

CsBr contains bcc structure. The length of its one side is 4.3 Å. The minimum distance between Cs⁺ and Br⁻ ions will be ______.

Options

• 0.897 Å

• 3.72 Å

• 1.794 Å

• none of these

Answer 1

CsBr contains bcc structure. The length of its one side is 4.3 Å. The minimum distance between Cs⁺ and Br⁻ ions will be 3.72 Å.

Explanation:

Given: Edge length (a) = 4.3 Å

Length of body diagonal = `sqrt 3 a`

In bcc, the Cs⁺ and Br⁻ ions are located at the corners and centre, so the distance between them is half the body diagonal:

∴ Minimum distance = `(sqrt 3 * a)/2`

= `(sqrt3 * 4.3)/2`

= `(1.732 * 4.3)/2`

= `7.4476/2`

= 3.72 Å

∴ The minimum distance between Cs⁺ and Br⁻ ions will be 3.72 Å.