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Question
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11.
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Solution
Steps of construction:
Step 1: Draw a line segment AB of 11cm.
Step 2: Draw`∠`DAB = Y = 30° and `∠`FBA = `∠`Z = 90°
Step 3: Draw the angle bisector of `∠`DAB and `∠`EBA which intersect each other at x
Step 4: Draw the perpendicular bisector XA and XB which intersect AB at Y and Z respectively.
Step 5: Join XY and XZ
∴ Δ XYZ is the required triangle
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