Question

Construct a paralIelogra m PQRS in wh i di QR = 5. 4 cm , SR = 6. 0 cm and ∠ Q= 60°. Draw its lines of symmetry, if possible. 

Answer 1

Steps construction :

(i) Draw a line segment QR = 5.4 cm 

(ii) At Q , draw a ray making an angle of 60 degrees with QR and OJt QP = SR = 6cm 

(iii) Pas centre draw an arc equal to 5. 4 cm 

(iv) Ras centre draw an arc equal to 6 cm which intersects the first arc at S. 

(v) Join RS and PS. PQRS is the required parallelogram. 

(vi) Join QS and PR which intersect each other at 0. 

There is no line of symmetry of parallelogram PQRS but it has one point symmetry which is 0, the point of intersection of its diagonals.