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Question
Construct a 3 × 4 matrix, whose elements are given by:
aij = 2i – j
Sum
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Solution
In general, a 3 × 4 matrix is given by A = `[(a_11, a_12, a_13, a_14), (a_21, a_22, a_23, a_24), (a_31, a_32, a_33, a_34)]`
⇒ aij = 2i – j, i = 1, 2, 3 and j = 1, 2, 3, 4
∴ a11 = 2 × 1 – 1
= 2 – 1
= 1
a21 = 2 × 2 – 1
= 4 – 1
= 3
a31 = 2 × 3 – 1
= 6 – 1
= 5
⇒ a12 = 2 × 1 – 2
= 2 – 2
= 0
a22 = 2 × 2 – 2
= 4 – 2
= 2
a32 = 2 × 3 – 2
= 6 – 2
= 4
⇒ a13 = 2 × 1 – 3
= 2 – 3
= –1
a23 = 2 × 2 – 3
= 4 – 3
= 1
a33 = 2 × 3 – 3
= 6 – 3
= 3
⇒ a14 = 2 × 1 – 4
= 2 – 4
= –2
a24 = 2 × 2 – 4
= 4 – 4
= 0
a34 = 2 × 3 – 4
= 6 – 4
= 2
Therefore, the required matrix is A = `[(1, 0, -1, -2),(3, 2, 1, 0),(5, 4, 3, 2)]`.
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