Question

Consider two identical dipoles D₁ and D₂. Charges −q and q of dipole D₁ are located at (0, 0) and (a, 0) and that of dipole D₂ at (0, a) and (0, 2a) in x-y plane, respectively. The net dipole moment of the system is ______.

Options

• `qa(hat i + hat j)`

• `-qa(hat i + hat j)`

• `qa(hat i - hat j)`

• `-qa(hat i - hat j)`

Answer 1

Consider two identical dipoles D₁ and D₂. Charges −q and q of dipole D₁ are located at (0, 0) and (a, 0) and that of dipole D₂ at (0, a) and (0, 2a) in x-y plane, respectively. The net dipole moment of the system is `bbunderline(qa(hat i + hat j))`.

Explanation:

The dipole moment is given by:

p = q.(displacement from −q to +q)

For diode D₁, the charges −q and +q are located at (0, 0) and (a, 0), respectively,

p₁ = `q a hat i`

For diode D₂, the charges −q and +q are located at (0, a) and (a, 2a), respectively,

p₂ = `q a hat j`

Net dipole moment,

P_net = p₁ + p₂

= `q a hat i + q a hat j`

= `q a(hat i + hat j)`