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Question
Consider the following distribution of daily wages of 50 workers of a factory:
| Daily wages (in ₹) |
500-520 | 520-540 | 540-560 | 560-580 | 580-600 |
| Number of workers | 12 | 14 | 8 | 6 | 10 |
Find the mean daily wages of the workers of the factory by using an appropriate method.
Sum
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Solution
To find the class mark for each interval, the following relation is used.
xi = `("Upper class limits + Lower class limits")/2`
Class size (h) of this data = 20
Taking 550 as assured mean (a), di, ui, and fiui can be calculated as follows:
| Daily wages (in Rs) |
Number of workers (fi) | xi | di = xi − 550 | ui = `d_i/20` | fiui |
| 500 - 520 | 12 | 510 | - 40 | − 2 | − 24 |
| 520 - 540 | 14 | 530 | - 20 | − 1 | − 14 |
| 540 - 560 | 8 | 550 | 0 | 0 | 0 |
| 560 - 580 | 6 | 570 | 20 | 1 | 6 |
| 580 - 600 | 10 | 590 | 40 | 2 | 20 |
| Total | ∑fi = 50 | - | - | -12 |
From the table, it can be observed that
∑fi = 50
∑fiui = −12
Mean, `barx = a+((∑f_i"u"_i)/(∑f_i))h`
`= 550+((-12)/50)20`
`= 550 - 24/5`
= 550 - 4.8
= 545.20
Therefore, the mean daily wage of the workers of the factory is Rs. 545.20.
shaalaa.com
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