Advertisements
Advertisements
Question
Consider the elements : Cs, Ne, I and F
Identify the element which exhibits neither the negative nor does the positive oxidation state.
Advertisements
Solution
The oxidation state of Ne is zero. It exhibits neither negative nor positive oxidation states.
RELATED QUESTIONS
Assign oxidation numbers to the underlined element in the following species:
NaH2PO4
Assign oxidation numbers to the underlined element in the following species:
NaHSO4
Assign oxidation numbers to the underlined elements in the following species:
NaBH4
Assign oxidation numbers to the underlined elements in the following species:
H2S2O7
Assign oxidation numbers to the underlined elements in the following species:
KAl(SO4)2.12 H2O
What are the oxidation numbers of the underlined elements in the following and how do you rationalise your results?
KI3
Consider the elements: Cs, Ne, I and F
Identify the element that exhibits only negative oxidation state.
Consider the elements: Cs, Ne, I and F
Identify the element that exhibits both positive and negative oxidation states.
In which of the following compounds, an element exhibits two different oxidation states.
The exhibition of various oxidation states by an element is also related to the outer orbital electronic configuration of its atom. Atom(s) having which of the following outermost electronic configurations will exhibit more than one oxidation state in its compounds.
(i) 3s1
(ii) 3d14s2
(iii) 3d24s2
(iv) 3s23p3
\[\ce{PbO}\] and \[\ce{PbO2}\] react with \[\ce{HCl}] according to following chemical equations:
\[\ce{2PbO + 4HCl -> 2PbCl2 + 2H2O}\]
\[\ce{PbO2 + 4HCl -> PbCl2 + Cl2 + 2H2O}\]
Why do these compounds differ in their reactivity?
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2SO4}\]
The oxidation number of P in Mg2P207 is ____________.
The oxidation number and covalency of sulphur in sulphur molecules (Sg) are:
Oxidation number of potassium in K2O, K2O2 and KO2, respectively, is ______.
On reaction with a stronger oxidizing agent like KIO4, hydrogen peroxide with the evolution of O2. The oxidation number of I in KIO4 changes to ______.
Oxidation state of sulphur in anions `"SO"_3^(2-)`, `"S"_2"O"_4^(2-)` and `"S"_2"O"_6^(2-)` increases in the orders:
