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Question
Consider the compound, BCl3. How will BCl3 behave with water? Justify.
Short/Brief Note
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Solution
Being a Lewis acid, BCl3 readily undergoes hydrolysis. Boric acid is formed as a result.
\[\ce{BCl3 + 3H2O -> 3HCl + B(OH)3}\]
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Important Trends and Anomalous Behaviour of Carbon
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