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Question
Consider the following distribution of daily wages of 50 worker of a factory.
|
Daily wages (in Rs) |
100 − 120 |
120 − 140 |
140 −1 60 |
160 − 180 |
180 − 200 |
|
Number of workers |
12 |
14 |
8 |
6 |
10 |
Find the mean daily wages of the workers of the factory by using an appropriate method.
Sum
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Solution
To find the class mark for each interval, the following relation is used.
x_i = ("Upper class limits + Lower class limits")/2
Class size (h) of this data = 20
Taking 150 as assured mean (a), di, ui, and fiui can be calculated as follows.
|
Daily wages (in Rs) |
Number of workers (fi) | xi | di = xi − 15 | ui = di/20 | fiui |
| 100 −120 | 12 | 110 | − 40 | − 2 | − 24 |
| 120 − 140 | 14 | 130 | − 20 | − 1 | − 14 |
| 140 − 160 | 8 | 150 | 0 | 0 | 0 |
| 160 −180 | 6 | 170 | 20 | 1 | 6 |
| 180 − 200 | 10 | 190 | 40 | 2 | 20 |
| Total | 50 | -12 |
From the table, it can be observed that
`sum f_i = 50`
`sumf_iu_i = -12`
Mean, `barx = a+((sumf_i"u"_i)/(sumf_i))h`
= 150+(-12/50)20
= 150 - 24/5
= 150 - 4.8
= 145.2
Therefore, the mean daily wage of the workers of the factory is Rs 145.20
shaalaa.com
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