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Consider an ideal gas with following distribution of speeds. Speed (m/s) % of molecules 20 10 400 20 600 40 800 20 1000 10 - Physics

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Question

Consider an ideal gas with following distribution of speeds.

Speed (m/s) % of molecules
20 10
400 20
600 40
800 20
1000 10

If all the molecules with speed 1000 m/s escape from the system, calculate new Vrms and hence T.

Long Answer
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Solution

When molecules escape 1000 ms–1 out then,

`v_(rms)^2 = (10 xx (200)^2 + 20 xx (400)^2 + 40 xx (600)^2 + 20 xx (800)^2)/(10 + 20 + 40 + 20)`

`v_(rms)^2 = (10^5 [4 + 32 + 144 + 128])/90`

`v_(rms) = sqrt((10^5[308])/90)`

= `sqrt(10^4/9 xx 308`

= `100/3 sqrt(308)`

= `33.33 xx 17.55 ≅ 582  ms^-1`

`T = 1/3 (mv_(rms)^2)/K_B`

= `(3 xx 10^-26 xx (585)^2)/(3 xx 1.38 xx 10^-23)`

= `(585)^2/138 xx 10^(-24 + 23)`

`T = 4.24 xx 10^-1 xx 585`

= 248.04 K

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RMS Speed of Gas Molecules
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Chapter 13: Kinetic Theory - Exercises [Page 95]

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NCERT Exemplar Physics [English] Class 11
Chapter 13 Kinetic Theory
Exercises | Q 13.28 (ii) | Page 95

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