Advertisements
Advertisements
Question
Concentration of the Ag+ ions in a saturated solution of Ag2C2O4 is 2.24 × 10−4 mol L−1 solubility product of Ag2C2O4 is ____________.
Options
2.24 × 10−8 mol3 L−3
2.66 × 10−12 mol3 L−3
4.5 × 10−11 mol3 L−3
5.619 × 10−12 mol3 L−3
Advertisements
Solution
Concentration of the Ag+ ions in a saturated solution of Ag2C2O4 is 2.24 × 10−4 mol L−1 solubility product of Ag2C2O4 is 5.619 × 10−12 mol3 L−3.
Explanation:
\[\ce{Ag2C2O4 ⇌ 2Ag^+ + C2O^{2-}_4}\]
[Ag+] = 2.24 × 10−4 mol L−1
\[\ce{[C2O^{2-}_4]}\] = `(2.24 xx 10^-4)/2` mol L−1
= 1.12 × 10−4 mol L−1
Ksp = \[\ce{[Ag^+]^2 [C2O^{2-}_4]}\]
= (2.24 × 10−4 mol L−1)2 (1.12 × 10−4 mol L−1)
= 5.619 × 10−12 mol3 L−3
APPEARS IN
RELATED QUESTIONS
Answer the following :
Explain the relation between ionic product and solubility product to predict whether a precipitate will form when two solutions are mixed?
The solubility of BaSO4 in water is 2.42 × 10−3 g L−1 at 298 K. The value of its solubility product (Ksp) will be:
(Given molar mass of BaSO4 = 233 g mol−1)
The solubility of AgCl(s) with solubility product 1.6 × 10−10 in 0.1 M NaCl solution would be ____________.
If the solubility product of lead iodide is 3.2 × 10−8, its solubility will be ____________.
Solubility product of Ag2CrO4 is 1 × 10−12. What is the solubility of Ag2CrO4 in 0.01 M AgNO3 solution?
Ksp of Ag2CrO4 is 1.1 × 10−12. what is the solubility of Ag2CrO4 in 0.1 M K2CrO4?
The solubility product of AgBr is 5.2 × 10−13 Calculate its solubility in mol dm−3 and g dm−3 (Molar mass of AgBr = 187.8g mol−1)
The relationship between solubility and solubility product for silver carbonate is ______.
The solubility of silver sulphate is 1.85 x 10-2 mol dm-3. Calculate solubility product of silver sulphate.
Derive the relationship between solubility and solubility product of AgBr.
