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Question
Compare the structures of white phosphorus, P4O6 and P4O10.
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Solution
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White phosphorus (P4) has a tetrahedral structure consisting of four phosphorus atoms at the corners of a regular tetrahedron. Each P atom is bonded to the other three phosphorus atoms with a bond angle of 60°.
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P4O6 structure is formed by replacing the \[\ce{P - P}\] bonds of P4 with \[\ce{P - O - P}\] linkages, maintaining a similar tetrahedral-like cage but with oxygen atoms bridging phosphorus atoms.
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P4O10 also has a cage-like structure similar to P4O6 but with more oxygen atoms attached, resulting in a fully oxidised phosphorus pentoxide molecule (P4O10) with phosphorus atoms bonded to oxygen atoms, forming \[\ce{P = O}\] bonds and \[\ce{P - O - P}\] bridges.
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White phosphorus is elemental and consists only of phosphorus atoms, while P4O6 and P4O10 are molecular oxides of phosphorus with oxygen atoms incorporated, making their structures more complex with bridging and double bonds.
Thus, white phosphorus is a tetrahedral P4 molecule, P4O6 is a less oxidised cage with \[\ce{P - O - P}\] bridges, and P4O10 is a more oxidised, fully oxygenated cage structure.
