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Co-ordinates of a point on the curve y = x sin x at which the normal is parallel to the line 4x + 4y = 3 are ______.

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Question

Co-ordinates of a point on the curve y = x sin x at which the normal is parallel to the line 4x + 4y = 3 are ______.

Options

  • `(- pi/2, - pi/2)`

  • `(pi/2, - pi/2)`

  • `(- pi/2, pi/2)`

  • `(pi/2, pi/2)`

MCQ
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Solution

Co-ordinates of a point on the curve y = x sin x at which the normal is parallel to the line 4x + 4y = 3 are `underline((pi/2, pi/2))`.

Explanation:

y = x sin x    ...(i)

`therefore "dy"/"dx" = x cos x + sin x`

Slope of the normal = - `1/("dy"/"dx") = (- 1)/(x cos x + sin x)`

Slope of the given line is - 1.

Since the normal is parallel to the given line.

`therefore (- 1)/(x cos x + sin x) = - 1`

⇒ x cos x + sin x = 1

⇒ x = `pi/2`

From (i), y = `pi/2`

∴ Co-ordinates of the point are `(pi/2, pi/2)`.

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Application of Derivative in Geometry
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