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Question
Co-ordinates of a point on the curve y = x sin x at which the normal is parallel to the line 4x + 4y = 3 are ______.
Options
`(- pi/2, - pi/2)`
`(pi/2, - pi/2)`
`(- pi/2, pi/2)`
`(pi/2, pi/2)`
MCQ
Fill in the Blanks
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Solution
Co-ordinates of a point on the curve y = x sin x at which the normal is parallel to the line 4x + 4y = 3 are `underline((pi/2, pi/2))`.
Explanation:
y = x sin x ...(i)
`therefore "dy"/"dx" = x cos x + sin x`
Slope of the normal = - `1/("dy"/"dx") = (- 1)/(x cos x + sin x)`
Slope of the given line is - 1.
Since the normal is parallel to the given line.
`therefore (- 1)/(x cos x + sin x) = - 1`
⇒ x cos x + sin x = 1
⇒ x = `pi/2`
From (i), y = `pi/2`
∴ Co-ordinates of the point are `(pi/2, pi/2)`.
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Application of Derivative in Geometry
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