Question

\[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{......}\ce{Cl}
\end{array}\]  obtained by chlorination of n-butane, will be

Options

• `l` - form

• d - form

• Meso form

• Racemic mixture

Answer 1

Racemic mixture

Explanation:

Chlorination ofn-butane takes place via free radical formation i.e., \[\ce{Cl2 ->[hv] C\overset{\bullet}{l} + C\overset{\bullet}{l}}\]

\[\ce{C\overset{\bullet}{l}}\] may attack on either side and give a racemic mixture of 2-chlorbutane which contain 50% d - form and 50% `l` - form.