English
Tamil Nadu Board of Secondary EducationHSC Commerce Class 12

Choose the correct alternative: If for a binomial distribution b(n, p) mean = 4 and variance = 4/3, the probability, P(X ≥ 5) is equal to

Advertisements
Advertisements

Question

Choose the correct alternative:

If for a binomial distribution b(n, p) mean = 4 and variance = 4/3, the probability, P(X ≥ 5) is equal to

Options

  • (2/3)6

  • (2/3)5(1/3)

  • (1/3)6

  • 4(2/3)6

MCQ
Advertisements

Solution

4(2/3)6

shaalaa.com
Distribution
  Is there an error in this question or solution?
Chapter 7: Probability Distributions - Exercise 7.4 [Page 169]

APPEARS IN

Samacheer Kalvi Business Mathematics and Statistics [English] Class 12 TN Board
Chapter 7 Probability Distributions
Exercise 7.4 | Q 10 | Page 169

RELATED QUESTIONS

Write down the condition for which the binomial distribution can be used.


If the probability of success is 0.09, how many trials are needed to have a probability of atleast one success as 1/3 or more?


The average number of customers, who appear in a counter of a certain bank per minute is two. Find the probability that during a given minute no customer appears


Choose the correct alternative:

If X ~ N(9, 81) the standard normal variate Z will be


Choose the correct alternative:

A manufacturer produces switches and experiences that 2 percent switches are defective. The probability that in a box of 50 switches, there are atmost two defective is :


Choose the correct alternative:

The average percentage of failure in a certain examination is 40. The probability that out of a group of 6 candidates atleast 4 passed in the examination are


Choose the correct alternative:

Which of the following cannot generate a Poisson distribution?


Choose the correct alternative:

The weights of newborn human babies are normally distributed with a mean of 3.2 kg and a standard deviation of 1.1 kg. What is the probability that a randomly selected newborn baby weight less than 2.0 kg?


Choose the correct alternative:

If P(Z > z) = 0.8508 what is the value of z (z has a standard normal distribution)?


The annual salaries of employees in a large company are approximately normally distributed with a mean of $50,000 and a standard deviation of $20,000. What percent of people earn between $45,000 and $65,000?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×