Advertisements
Advertisements
Question
Check whether the lines given by `(x - 1)/2 = (y - 2)/3 = (z - 3)/4 and (x - 4)/5 = (y - 1)/2 = z` are parallel or not. If parallel, find the distance between them, otherwise find their point of intersection, if the lines are intersecting.
Advertisements
Solution
Given lines:
`(x - 1)/2 = (y - 2)/3 = (z - 3)/4 and (x - 4)/5 = (y - 1)/2 = z`
For the first line, direction ratios are (2, 3, 4),
For the second line:
`(x - 4)/5 = (y - 1)/2 = (z - 0)/1`, direction ratios are (5, 2, 1),
Since `2/5 ≠ 3/2 ≠ 4/1`, the lines are not parallel.
Now let the first line be:
x = 1 + 2λ, y = 2 + 3λ, z = 3 + 4λ
Second line:
x = 4 + 5μ, y = 1 + 2μ, z = μ
Let’s equate them:
1 + 2λ = 4 + 5μ ....(1)
2 + 3λ = 1 + 2μ ....(2)
3 + 4λ = μ ....(3)
From third equation: μ = 3 + 4λ ....(4)
Substitute equation (4) in the second:
2 + 3λ = 1 + 2(3 + 4λ)
2 + 3λ = 7 + 8λ
−5 = 5λ
∴ λ = −1
Let’s put λ = −1 in equation (4):
μ = 3 + 4(−1)
μ = 3 + (−4)
∴ μ = −1
Now substitute λ = −1 and μ = −1 in equation (1):
1 + 2(−1) = 4 + 5(−1)
−1 = −1
So lines intersect.
Point of intersection:
- x = 1 + 2(−1) = −1
- y = 2 + 3(−1) = −1
- z = 3 + 4(−1) = −1
Hence, the two lines are not parallel, and they intersect; their point of intersection is (−1, −1, −1).
