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Cerium (IV) has a noble gas configuration. Which of the following is a correct statement about it? - Chemistry (Theory)

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Question

Cerium (IV) has a noble gas configuration. Which of the following is a correct statement about it?

Options

  • It will not prefer to undergo redox reactions.

  • It will prefer to gain electron and act as an oxidizing agent.

  • It will prefer to give away an electron and behave as reducing agent.

  • It acts as both oxidizing and reducing agent.

MCQ
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Solution

It will prefer to gain electron and act as an oxidizing agent.

Explanation:

Cerium (IV) means Ce4+. Its electronic configuration is the same as the noble gas xenon [Xe]. This makes it electron-deficient and highly unstable. So, it easily gains one electron to become Ce3+ (more stable). This means Ce4+ acts as a strong oxidising agent.

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Chapter 8: d-and ƒ-Block Elements - OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS [Page 503]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 8 d-and ƒ-Block Elements
OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS | Q 110. | Page 503
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