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Question
Calculate the van't Hoff factor assuming the complete dissociation of NaBr in its aqueous solution.
Short/Brief Note
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Solution
\[\ce{NaBr -> Na^+ + Br^-}\]
i = `"Moles of particles after dissociation"/"Moles of particles dissolved"`
I = `2/1`
= 2
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Colligative Properties of Electrolytes
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