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Question
Calculate the quantity of electricity that would be required to reduce 12.3 g of nitrobenzene to aniline, if the current efficiency is 50%.
Numerical
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Solution
Reduction of nitrobenzene (C6H5NO2) to aniline (C6H5NH2) requires 6 electrons per molecule:
\[\ce{C6H5NO2 + 6 e- + 6 H+ -> C6H5NH2 + 2H2O}\]
Molar mass of C6H5NO2 = 123 g/mol
Moles = `12.3/123` = 0.1 mol
Electrons required = 0.1 mol × 6 mol e−
= 0.6 mol e−
`Q_"actual"` = 0.6 × 96500 = 57900 C
Since current efficiency = 50%, the actual electricity needed is
`Q_"supplied" = 57900/0.50` = 115800 C
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