Question

Calculate the quantity of electricity required to produce 0.42 g Ag at cathode during the electrolysis of AgNO₃ solution. (Molar mass Ag = 108 g mol^-1)

Options

• 257.1 C

• 375.3 C

• 965.0 C

• 470.0 C

Answer 1

375.3 C

Explanation

Given,
Mass at cathode = 0.42 g
Molar mass of Ag = 108 g/mol
Quantity of electricity = ?
The reaction involved in the given question is

\[\ce{Ag+ + e- -> Ag}\]

So, mole ratio = `1/1` = 1

Now to calculate the amount of electricity required use the formula.

Amount of electricity = `("Mass of Ag" xx 96500)/("Mole ratio" xx "Molar mass")`

`= (0.42 xx 96500)/(1 xx 108)`

= 375.3 C

`:.` Amount of electricity required is 375.3 C.