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Question
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2S2O3}\]
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Solution
Let x = oxidation number of sulphur, and +1 is oxidation number of \[\ce{Na}\], –2 is oxidation number of \[\ce{O}\], also we can assume total charge on compound = 0 then solving we get.
+2 + 2x – 6 = 0
x = +2.
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