Question

Calculate the oxidation number of Ag in K[Ag(CN)₂].

Answer 1

K⁺ → charge = +1

Complex ion: [Ag(CN)₂]^– → overall charge = –1

Let oxidation number of Ag = x

Each CN = –1

Total from 2 CN = –2

Putting the value in formula,

∴ x + (–2) = –1

x – 2 = –1

x = –1 + 2

x = +1

∴ The oxidation number of Ag in K[Ag(CN)₂] is +1.