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Question
Calculate the % of oxygen in Al2(SO4)3. (Atomic mass: Al-27, O-16, S -32)
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Solution
Aluminum Sulphate – Al2(SO4)3
Molar mass of Aluminium Sulphate = (27 × 2) + (32 × 3) + (16 × 12) = 54 + 96 + 192 = 342 g
% of Oxygen = `192/342 × 100` = 56.14%.
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