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Question
Calculate the molecular mass of the following:
Ammonium chloroplatinate (NH4)2 PtCl6
[At mass: C = 12, H = 1, O = 16, Cl = 35.5, N = 14, Cu = 63.5, S = 32, K = 39, Pt = 195, Ca = 40, P = 31, Mg = 24]
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Solution
(NH4)2 PtCl6
= 2(14 + 4 × 1) + 195 + 35.5 × 6
= 36 + 195 + 213
= 444 amu
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