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Question
Calculate the molar mass of an element having density 2.8 g cm−3 and forms fcc unit cell.
[a3.NA = 38.5 cm3 mol−1]
Options
26.95 g mol−1
23.5 g mol−1
29.2 g mol−1
21.6 g mol−1
MCQ
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Solution
26.95 g mol−1
Explanation:
For fcc unit cell, n = 4.
Density `(rho) = (Mn)/(a^3 N_A)`
`2.8 = (M xx 4)/38.5`
`M = (2.8xx38.5)/4`
= 26.95 g mol−1
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Cubic System
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