Advertisements
Advertisements
Question
Calculate the Mean, Median and Mode of the following data:
5, 10, 10, 12, 13.
Are these three equal?
Advertisements
Solution
Given data is 5, 10, 10, 12, 13.
Sum of all observations = 5 + 10 + 10 + 12 + 13 = 50
Number of observations = 5
Mean = `"Sum of all observations"/"Total observations" = 50/5` = 10
Here, n = 5 ...(Odd)
So, Median = Value of `((n + 1)/2)^(th)` observation
= Value of `((5 + 1)/2)^(th)` observation
= Value of 3rd observation = 10
Mode = Most frequent data = 10
Hence, Mean = Median = Mode
Yes, Mean, median and mode are equal.
APPEARS IN
RELATED QUESTIONS
A cricketer scores the following runs in eight innings:
58, 76, 40, 35, 46, 45, 0, 100
Find the mean score.
Solve any two of the following.
Find the mean of the data given in the following table.
| Class | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 |
| Frequency | 6 | 4 | 5 | 7 | 3 |
The` "n"^(th)` term of the A. P. 3, 8, 13, 18, ............ is 148. Find n
There are 40 students in a class, out of them 15 are boys. The mean of marks obtained by boys is 33 and that for girls is 35. Find out the mean of all students in the class.
In a week, temperature of a certain place is measured during winter are as follows 26°C, 24°C, 28°C, 31°C, 30°C, 26°C, 24°C. Find the mean temperature of the week
The average of two numbers are 20. One number is 24, another number is ____________
The mean of three numbers is 40. All the three numbers are different natural numbers. If lowest is 19, what could be highest possible number of remaining two numbers?
If the arithmetic mean of 8, 4, x, 6, 2, 7 is 5, then the value of x is ______.
Mean can never be a fraction.
The following are weights (in kg) of 12 people. 70, 62, 54, 57, 62, 84, 75, 59, 62, 65, 78, 60. How many people weigh above the mean weight?
