Question

Calculate the mass of the solute in the following solution:

250 cm³ of 2M HNO₃

Answer 1

Given: Volume of solution = 250 cm³ = 0.250 L

Molarity (M) = 2 M

Acid = HNO₃ (monoprotic acid)

Molar mass of HNO₃ = 63 g/mol

Mass of solute = Molarity × Molar mass × Volume (L)

Mass = 2 × 63 × 0.250

Mass = 31.5 g

∴ 31.5 g of HNO₃ is present in 250 cm³ of 2 M solution.