Advertisements
Advertisements
Question
Calculate the mass of silver deposited at cathode when a current of 2 amperes is passed through a solution of AgNO3 for 15 minutes.
(at. wt. of Ag = 108, 1 F = 96500 C)
Numerical
Advertisements
Solution
A = 108
E = `A/1`
= `108/1`
= 108
z = `E/96500`
= `108/96500` g/c
I = 2 amperes
t = 15 × 60 = 900 sec.
w = z × I × t
= `108/96500 xx 2 xx 900`
= `(216 xx 9)/965`
= `1944/965`
= 2.014 g
shaalaa.com
States of Matters: Structure and Properties Solid State - Calculation of the Number of Atoms per Unit Cell
Is there an error in this question or solution?
Chapter 3: Electrochemistry - QUESTIONS FROM ISC EXAMINATION PAPERS [Page 215]
