Question

Calculate the equivalent conductivity of 1 M H₂SO₄, whose specific conductivity is 26 × 10⁻² ohm⁻¹ cm⁻¹.

Answer 1

Conductivity (κ) = 26 × 10⁻² ohm⁻¹ cm⁻¹

Normality (N) = 2 (since 1 M H₂SO₄ gives 2 equivalents per mole)

To calculate the equivalent conductance (Λ_eq​) of a solution, use the formula:

`Lambda_(eq) = (kappa xx 1000)/N`

= `(26 xx 10^-2 xx 1000)/2`

= `260/2`

= 130 S cm² eq⁻¹

∴ The equivalent conductance of 1 M H₂SO₄ solution is 130 S cm² eq⁻¹.