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Question
Calculate the constant external pressure required to expand 2 moles of an ideal gas from volume 15 dm³ to 20 dm³ if amount of work done is -600 J.
[Note: The question has been modified to get the correct answer.]
Options
1.2 bar
1.5 bar
1.8 bar
2.1 bar
MCQ
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Solution
1.2 bar
Explanation:
1 bar dm3 × 100 = J
V1 = 15 dm3
V2 = 20 dm3
W = −PextΔV
\[\mathrm{P_{ext}}=-\frac{\mathrm{W}}{\Delta\mathrm{V}}=-\frac{\mathrm{W}}{\left(\mathrm{V_{2}}-\mathrm{V_{1}}\right)}\]
\[\mathrm{P_{ext}=-\frac{\left(-600\right)J}{\left(20-15\right)dm^{3}}=\frac{600J}{5dm^{3}}\times\frac{1dm^{3}bar}{100J}}\]
= 1.2 bar
[Note: In the question dm-3 is changed to dm3 to apply appropriate textual concepts. |
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Expression for Pressure-volume (PV) Work
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