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Question
Calculate the charge number of the complex ion:
[Pt(NH3)2Cl2]
Numerical
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Solution
Complex: [Pt(NH3)2Cl2]
Let the oxidation number of Pt be x.
NH3 (neutral ligand) has a charge of 0 each.
There are 2 NH3 ions, so total charge from ligands = 2 × (0) = 0.
Cl− is a monodentate anionic ligand that has a charge of −1 each.
There are 2Cl− ions = −2
Overall charge on the complex = +1
x + 2(0) + 2(−1) = 0
x − 2 = 0
x = +2
The oxidation number of Pt is +2.
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Chapter 9: Coordination Compounds - Review Exercises [Page 517]
