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Question
Calculate the charge number of the complex ion:
[Co(NH3)4Cl2]+
Numerical
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Solution
Complex: [Co(NH3)4Cl2]+
Let the oxidation number of Co be x.
NH3 (neutral ligand) has a charge of 0 each.
There are 4 NH3 ions, so total charge from ligands = 4 × (0) = 0.
Cl− is a monodentate anionic ligand that has a charge of −1 each.
There are 2Cl− ions = −2
Overall charge on the complex = +1
x + 4(0) + 2(−1) = +1
x − 2 = +1
x = +3
The oxidation number of Co is +3.
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