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Question
Calculate approximately the ratio of the nuclear radii of the gold isotope \[_{79}^{197}Au\] and the silver isotope \[_{47}^{107}Ag\].
Options
1.23
1.13
1.25
1.33
MCQ
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Solution
1.23
Explanation:
Given that,
Nuclear radius of the gold isotope 79Au197 = RAu
Nuclear radius of the silver isotope 47Ag107 = RAg
Mass number of gold, AAu = 197
Mass number of silver, AAg = 107
The ratio of the radii of the two nuclei is related with their mass numbers:
\[\frac{R_{\mathrm{Au}}}{R_{\mathrm{Ag}}}=\left(\frac{R_{\mathrm{Au}}}{R_{\mathrm{Ag}}}\right)^{\frac{1}{3}}=\left(\frac{197}{107}\right)^{\frac{1}{3}}=1.2256\]
So, the ratio of the nuclear radii of the gold and silver isotopes is about 1.23.
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Size of the Nucleus
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