Question

Calculate \[\ce{\wedge^0_m BaCl2 and Al2(SO4)}\]   from the following data.

For \[\ce{\wedge^0_m Ba^2+ = 127.2 S cm^2 mol^{-1}, \wedge^0_m Al^3+ = 189 S cm^2 mol^{−1}}\]\[\ce{\wedge^0_m Cl= 76.3 S cm^2 mol^{-1}, \wedge^0_m SO^2-_4 = 160 S cm^2 mol^{-1}}\]

Answer 1

\[\ce{\wedge^0_m (BaCl2) = \wedge^0_m (Ba^{+2})+ 2\wedge^0_m (Cl^-)}\]

= 127.2 + 2 × 76.3

= 279.8 S cm² mol⁻¹

\[\ce{\wedge^0_m(Al2(SO4)3) = 2\wedge^0_m(Al^{+3}) + 3\wedge^0_m(SO^2-_4)}\]

= 2 × 189 + 3 × 160

= 858 S cm² mol⁻¹