Question

Calcium carbonate react with dilute hydrochloric acid as given below:

\[\ce{CaCO3 + 2HCl -> CaCl2 + H2O + CO2}\]

What is the mass of 5 moles of calcium carbonate? (Relative molecular mass of calcium carbonate is 100)

Answer 1

1 mole of \[\ce{CaCO3}\] = 100 g

5 moles of \[\ce{CaCO3 -> 5 × 100}\] = 500 g

Hence, the mass of 5 moles of \[\ce{CaCO3}\] will be 500 g