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Question
Balance the following equation:
\[\ce{P + O2->P2O5}\]
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Solution
\[\ce{P + O2->P2O5}\]
To balance O atoms on both sides
\[\ce{P + 5O2->2P2O5}\]
There are 4 P atoms on RHS
∴ Make P atoms 4 on LHS
\[\ce{4P + 5O2->2P2O5}\]
Atoms of P and O are equal on both sides.
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