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Question
Balance the following equation:
\[\ce{H2S + Cl2->S + HCl}\]
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Solution
\[\ce{H2S + Cl2->S + HCl}\]
Multiply HCl on the right side by 2 and atoms of H and Cl are balanced.
\[\ce{H2S + Cl2->S + 2HCl}\]
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