Question

Atomic numbers of elements A, B, C, D, E, F are 8, 7, 11, 12, 13 and 9 respectively. State the type of ions they form. 

Answer 1

The electronic configurations of the given elements are:

A = 8 (2, 6)

B = 7 (2, 5)

C = 11 (2, 8, 1)

D = 12 (2, 8, 2)

E = 13 (2, 8, 3)

F = 9 (2, 7)

Thus A, B, F will form anions and C, D, E will form cations.

Answer 2

Element	Atomic no.	Electronic configuration	Difference from Octet	Ion formed
A	8	2, 6	8 − 6 = 2	−2
B	7	2, 5	8 − 5 = 3	−3
C	11	2, 8, 1	One electron more than octet	+1
D	12	2, 8, 2	Two electrons more than octet	+2
E	13	2, 8, 3	Three electrons more than octet	+3
F	9	2, 7	8 − 7	−1