Advertisements
Advertisements
Question
At a particular locus, the frequency of allele A is 0.8, and that of allele a is 0.2. What would be the frequency of heterozygotes in a random mating population at equilibrium?
Options
0.32
0.16
0.24
0.48
Advertisements
Solution
0.32
APPEARS IN
RELATED QUESTIONS
Multiple choice question.
In Hardy - Weinberg equation, the frequency of homozygous recessive individual is represented by:
A population will not exist in Hardly Weiberg equilibrium if ____________.
Disturbance of Hardy - Weinberg equilibrium results in
For the MN-blood group system, the frequencies of M and N alleles are 0.7 and 0.3, respectively. The expected frequency of MN-blood group bearing organisms is likely to be ______.
In a certain population, the frequency of three genotypes is as follows:
| Genotypes: | BB | Bb | bb |
| frequency: | 22% | 62% | 16% |
What is the likely frequency of B and b alleles?
How is Hardy-Weinberg’s expression “(p2 + 2pq + q2) = 1” derived?
Write Hardy Weinberg's equation.
State Hardy Weinberg's principle.
The black colour on the beak of finches dominates over the yellow colour. There are 210 individuals with the genotype DD, 245 individuals with the genotype Dd and 45 individuals with the genotype dd. Deduce the frequency of individuals with dominant, heterozygous, and recessive traits.
Which one of the following factors will not affect the Hardy-Weinberg equilibrium?
