Question

At a certain 100 p of reduces 0.0/57 m carrier a current of 2 amp. The magnetic field at the centre of the coop is [`mu_0 = 4pi xx 10^-7` wb/amp – m]

Options

• 1.57 × 10^–5 weber/m²

• 8.0 × 10^–5 weber/m²

• 2.0 × 10^–5 weber/m²

• 3.14 × 10^–5 weber/m²

Answer 1

8.0 × 10^–5 weber/m² 

Explanation:

r = 0.15.7 m, J = 2 A

B = `(mu_0I)/(2r) = (4pi xx 10^-7 xx 2)/(2 xx 0.0157)` = 8 × 10^–5 weber/m²