Advertisements
Advertisements
Question
Assuming that the junction diode is ideal, the current in the arrangement shown in

Options
20 mA
10 mA
40 mA
30 mA
MCQ
Advertisements
Solution
20 mA
Explanation:
I = `(3 - 1)/100 = 2/100 = 2 xx 10^-2 = 20 xx 10^-3`A
shaalaa.com
A p-n Junction Diode
Is there an error in this question or solution?
