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Question
Assuming that the junction diode is ideal, the current in the arrangement shown in figure is ______.

Options
30 mA
40 mA
20 mA
10 mA
MCQ
Fill in the Blanks
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Solution
Assuming that the junction diode is ideal, the current in the arrangement shown in figure is 20 mA.
Explanation:
In the given circuit, the diode is forward biased, hence the current will flow through it

Now, applying KVL in the above circuit,
+3 - 100i - (+1) = 0
⇒ 3 - 1 = 100l
⇒ i = `2/100` = 0.02 A
i = 20 mA
Hence, the current flow in the circuit is 20 mA.
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